Completing The Square: Solving Quadratic Equations

by Andrew McMorgan 51 views

Hey math whizzes! Today, we're diving deep into a super useful technique for solving quadratic equations: completing the square. This method is not only a powerful tool in its own right but also the foundation for deriving the quadratic formula, so understanding it is key to unlocking a whole new level of algebraic mastery. We're going to tackle the equation x2βˆ’16x+54=0x^2 - 16x + 54 = 0 and walk through the steps together. Get ready to flex those math muscles, guys!

Understanding Quadratic Equations and Completing the Square

First off, let's quickly recap what a quadratic equation is. In its standard form, it looks like ax2+bx+c=0ax^2 + bx + c = 0, where aa, bb, and cc are constants, and aa is not zero. The 'x squared' term is what makes it quadratic. Now, solving these equations means finding the values of xx that make the equation true – these are often called the roots or solutions. There are several ways to do this: factoring, using the quadratic formula, and, of course, completing the square.

Completing the square is an algebraic manipulation technique used to rewrite a quadratic expression into a form where a perfect square trinomial is present. A perfect square trinomial is a trinomial that can be factored into the square of a binomial. For example, x2+6x+9x^2 + 6x + 9 is a perfect square trinomial because it factors into (x+3)2(x+3)^2. The magic of completing the square is that it allows us to isolate the squared term and then easily solve for xx by taking the square root of both sides. It's like strategically rearranging the pieces of the puzzle to reveal a simpler, solvable picture. This technique is particularly handy when the quadratic equation isn't easily factorable, which, let's be honest, happens a lot! We'll focus on the case where a=1a=1 for simplicity, as it is in our example equation x2βˆ’16x+54=0x^2 - 16x + 54 = 0. When aa is not 1, the first step is usually to divide the entire equation by aa to get it into this simpler form.

Step-by-Step: Solving x2βˆ’16x+54=0x^2 - 16x + 54 = 0

Alright, team, let's get our hands dirty with the equation x2βˆ’16x+54=0x^2 - 16x + 54 = 0. Our goal is to transform the left side of the equation, x2βˆ’16xx^2 - 16x, into a perfect square trinomial.

Step 1: Isolate the x2x^2 and xx terms.

First, we want to move the constant term (the number without an xx) to the right side of the equation. This gives us some breathing room to work on the left side. So, we subtract 54 from both sides:

x2βˆ’16x=βˆ’54x^2 - 16x = -54

This sets up the left side perfectly for our completing-the-square maneuver. Think of it as clearing the decks before we start building.

Step 2: Complete the square.

This is the core of the technique, guys! To make x2βˆ’16xx^2 - 16x into a perfect square trinomial, we need to add a specific constant term. How do we find this magic number? We take the coefficient of the xx term (which is -16 in our case), divide it by 2, and then square the result.

Let's break that down:

  • The coefficient of the xx term is -16.
  • Divide it by 2: βˆ’16/2=βˆ’8-16 / 2 = -8.
  • Square the result: (βˆ’8)2=64(-8)^2 = 64.

So, the number we need to add to complete the square is 64. Now, the crucial part: whatever we do to one side of the equation, we must do to the other side to maintain balance. So, we add 64 to both sides of our equation:

x2βˆ’16x+64=βˆ’54+64x^2 - 16x + 64 = -54 + 64

Step 3: Factor the perfect square trinomial.

Now that we've added 64, the left side, x2βˆ’16x+64x^2 - 16x + 64, is a perfect square trinomial. Remember how we found that magic number? It was by taking the coefficient of xx, dividing by 2, and squaring it. That number we got before squaring (which was -8) is exactly what goes inside the binomial. So, x2βˆ’16x+64x^2 - 16x + 64 factors into (xβˆ’8)2(x - 8)^2.

Let's check this: (xβˆ’8)2=(xβˆ’8)(xβˆ’8)=x2βˆ’8xβˆ’8x+64=x2βˆ’16x+64(x - 8)^2 = (x - 8)(x - 8) = x^2 - 8x - 8x + 64 = x^2 - 16x + 64. Perfect!

On the right side, we simply perform the addition: βˆ’54+64=10-54 + 64 = 10.

Our equation now looks like this:

(xβˆ’8)2=10(x - 8)^2 = 10

See how much simpler that is? We've transformed a quadratic equation into a form where we have a squared term equaling a constant. This is exactly what we wanted!

Step 4: Solve for xx.

To get xx by itself, we first need to undo the squaring. We do this by taking the square root of both sides of the equation. Remember, when you take the square root of a number, there are two possible results: a positive one and a negative one. So, we need to include the 'plus or minus' symbol (Β±\pm).

(xβˆ’8)2=Β±10\sqrt{(x - 8)^2} = \pm\sqrt{10}

This simplifies to:

xβˆ’8=Β±10x - 8 = \pm\sqrt{10}

Finally, to isolate xx, we add 8 to both sides:

x=8Β±10x = 8 \pm\sqrt{10}

And there you have it! The solutions to the equation x2βˆ’16x+54=0x^2 - 16x + 54 = 0 are x=8+10x = 8 + \sqrt{10} and x=8βˆ’10x = 8 - \sqrt{10}. We've successfully solved the equation by completing the square!

Filling in the Blanks: The Final Solution

So, to recap our journey, we started with x2βˆ’16x+54=0x^2 - 16x + 54 = 0. We manipulated it to the form (xβˆ’8)2=10(x - 8)^2 = 10.

When we solve this, we get xβˆ’8=Β±10x - 8 = \pm\sqrt{10}, which leads to x=8Β±10x = 8 \pm\sqrt{10}.

Therefore, the solutions are x=8+10x = 8 + \sqrt{10} and x=8βˆ’10x = 8 - \sqrt{10}.

If we were asked to fill in values for aa and bb in a specific format, let's imagine the solution was presented as x=aΒ±bx = a \pm \sqrt{b}. In our case, the value of aa would be 8 and the value of bb would be 10.

This confirms that our steps were correct and we've arrived at the final, simplified solutions. It’s awesome how completing the square transforms a potentially tricky quadratic into something manageable, right?

Why is Completing the Square Important?

Beyond just solving this specific equation, understanding how to complete the square is a foundational skill in algebra. It's the method used to derive the quadratic formula, which is a universal solution for any quadratic equation. Knowing this technique also helps in understanding other areas of mathematics, like conic sections (circles, ellipses, parabolas) where rewriting equations into standard forms often involves completing the square. It’s a building block that unlocks more complex concepts, so mastering it now will pay off big time as you progress in your math journey. Plus, it’s a pretty cool party trick for algebra nerds, if you ask me! The elegance of transforming an equation into a perfect square is something truly satisfying.

So there you have it, folks! A deep dive into solving x2βˆ’16x+54=0x^2 - 16x + 54 = 0 by completing the square. Keep practicing, and don't hesitate to tackle other quadratic equations using this method. The more you do it, the more intuitive it becomes. Happy solving!