Is This Number Rational? Math Quiz

by Andrew McMorgan 35 views

Hey math whizzes! Today, we're diving deep into the fascinating world of rational numbers. You know, those numbers that can be expressed as a simple fraction pq\frac{p}{q}, where 'p' and 'q' are integers and 'q' isn't zero? It sounds straightforward, but sometimes, especially with a mix of operations, it can get a little tricky to spot. We've got a question for you that’s sure to get those brain cells firing. We're going to look at four different expressions, and your mission, should you choose to accept it, is to identify which of the following is rational. Get ready to put your knowledge to the test, because understanding rational numbers is a fundamental building block in mathematics, and nailing this will give you a serious confidence boost. Let's break down each option, shall we?

Option A: 3π3 \cdot \pi

Alright guys, let's kick things off with option A: 3π3 \cdot \pi. So, what do we know about π\pi? This famous mathematical constant, approximately 3.14159..., is the ratio of a circle's circumference to its diameter. Now, the crucial piece of information here is that pi\\pi is an irrational number. This means it cannot be expressed as a simple fraction fracpq\\frac{p}{q}. Its decimal representation goes on forever without repeating. When you multiply an irrational number (like pi\\pi) by a non-zero rational number (like 3), the result is always an irrational number. Think about it: if 3π3 \cdot \pi were rational, say equal to fracab\\frac{a}{b}, then pi\\pi would be equal to fraca3b\\frac{a}{3b}, which would make pi\\pi rational. But we know that's not true! Therefore, 3π3 \cdot \pi is definitely not rational. So, toss this one out, and let's move on.

Option B: 23+9.26\frac{2}{3}+9.26

Next up, we have option B: 23+9.26\frac{2}{3}+9.26. This one looks a bit more promising, doesn't it? We're adding two numbers together. Let's analyze each part. The first part, frac23\\frac{2}{3}, is clearly a rational number because it's already in the form fracpq\\frac{p}{q} where p=2 and q=3. Now, what about 9.26? This is a terminating decimal. Any terminating decimal can be written as a fraction. For example, 9.269.26 can be written as frac926100\\frac{926}{100}. Since frac926100\\frac{926}{100} is a ratio of two integers, it's also a rational number. The sum of two rational numbers is always a rational number. So, when we add frac23\\frac{2}{3} and 9.269.26 (which is frac926100\\frac{926}{100}), the result will be rational. To be super sure, let's convert 9.269.26 to a fraction and add them: frac23+frac926100=frac2cdot1003cdot100+frac926cdot3100cdot3=frac200300+frac2778300=frac2978300\\frac{2}{3} + \\frac{926}{100} = \\frac{2 \\cdot 100}{3 \\cdot 100} + \\frac{926 \\cdot 3}{100 \\cdot 3} = \\frac{200}{300} + \\frac{2778}{300} = \\frac{2978}{300}. This is a fraction of two integers, so it's rational! Bingo! Option B is looking good, guys.

Option C: 45+36\sqrt{45}+\sqrt{36}

Let's take a look at option C, shall we? We've got sqrt45+sqrt36\\sqrt{45}+\\sqrt{36}. Here, we're adding two square roots. The key to figuring this out is to simplify each term. First, let's tackle sqrt36\\sqrt{36}. This is pretty straightforward: the square root of 36 is exactly 6. Since 6 can be written as frac61\\frac{6}{1}, it's a rational number. Now, let's look at sqrt45\\sqrt{45}. Can we simplify this? Yes, we can! We can rewrite 45 as 9cdot59 \\cdot 5. So, sqrt45=sqrt9cdot5=sqrt9cdotsqrt5=3sqrt5\\sqrt{45} = \\sqrt{9 \\cdot 5} = \\sqrt{9} \\cdot \\sqrt{5} = 3\\sqrt{5}. Now, here's the catch: sqrt5\\sqrt{5} is an irrational number. This is because 5 is not a perfect square. When we multiply an irrational number (sqrt5\\sqrt{5}) by a non-zero rational number (3), the result (3sqrt53\\sqrt{5}) is still irrational. So, option C is the sum of an irrational number (3sqrt53\\sqrt{5}) and a rational number (6). The sum of an irrational number and a rational number is always irrational. Therefore, sqrt45+sqrt36\\sqrt{45}+\\sqrt{36} is not rational. We're getting closer to the answer, but not quite there yet.

Option D: 14.3+5.7876523914 . \overline{3}+5.78765239

Finally, let's analyze option D: 14.3+5.7876523914 . \overline{3}+5.78765239. This involves adding two decimal numbers. The first number, 14.314.\overline{3}, is a repeating decimal. A crucial rule in mathematics is that all repeating decimals are rational numbers. The notation 14.314.\overline{3} means 14.3333...14.3333..., and it can be converted into a fraction. To convert 14.333...14.333... to a fraction, let x=14.333...x = 14.333.... Then 10x=143.333...10x = 143.333.... Subtracting the first from the second, we get 10xx=143.333...14.333...10x - x = 143.333... - 14.333..., which simplifies to 9x=1299x = 129. So, x=frac1299x = \\frac{129}{9}, which simplifies to frac433\\frac{43}{3}. This is clearly a rational number. The second number, 5.787652395.78765239, is a terminating decimal. As we discussed earlier, any terminating decimal is a rational number because it can be written as a fraction (in this case, frac578765239100000000\\frac{578765239}{100000000}). The sum of two rational numbers is always a rational number. Therefore, 14.3+5.7876523914.\overline{3}+5.78765239 is rational.

Conclusion: The Rational Choice!

So, after breaking down each option, we've found our winner! We examined 3π3 \cdot \pi, realizing that multiplying by pi\\pi always results in an irrational number. Then, we looked at frac23+9.26\\frac{2}{3}+9.26, a sum of two rational numbers, which is indeed rational. We also investigated sqrt45+sqrt36\\sqrt{45}+\\sqrt{36}, which simplified to an irrational number plus a rational number, resulting in an irrational number. Finally, we tackled 14.3+5.7876523914 . \overline{3}+5.78765239, the sum of a repeating decimal (rational) and a terminating decimal (rational), which confidently confirmed it as rational. Therefore, the correct answer to 'Which of the following is rational?' is Option D. Great job if you got it right, guys! Keep practicing, and you'll become rational number pros in no time!