Master Long Division: 825,470 ÷ 67

by Andrew McMorgan 35 views

Hey guys! Ready to tackle some serious math? Today, we're diving deep into the world of long division with a real doozy: 825,470÷67825,470 \div 67. Don't let those big numbers scare you off; we'll break it down step-by-step, making sure you understand every single move. Long division might seem intimidating at first, but it's a fundamental skill that builds a strong foundation for more complex mathematical concepts. Think of it like learning to ride a bike; a few wobbles at the start, but soon you'll be cruising. We're going to demystify this process, turning confusion into clarity. So, grab your pencils, get comfortable, and let's get this division party started! We'll not only find the quotient and remainder but also understand why each step works. It’s all about building that number sense and problem-solving muscle. Ready to conquer this challenge and impress yourself with your math prowess? Let's go!

Step 1: Setting Up the Problem

Alright, first things first, let's get our long division house in order. We're dividing 825,470825,470 by 6767. So, the number being divided, 825,470825,470, is our dividend, and it goes inside the division bracket. The number we're dividing by, 6767, is our divisor, and it goes outside to the left. Make sure you leave some space above the dividend for your quotient (the answer) and ample room to the right for your calculations. Visualizing the setup is key:

      _______
67 | 825470

Now, before we even start dividing, it's a good idea to get a feel for the divisor, 6767. Think about multiples of 6767. 67×1=6767 \times 1 = 67, 67×2=13467 \times 2 = 134, 67×10=67067 \times 10 = 670. This rough estimation helps us anticipate how many times 6767 will fit into parts of our dividend. For instance, we know 6767 is close to 7070, and 70×10=70070 \times 10 = 700, 70×100=700070 \times 100 = 7000. This gives us a ballpark idea of the magnitude of our answer. It’s like packing for a trip – you want to have a general idea of what you’ll need before you start. This initial estimation is a crucial part of the process, guys, and it’s often overlooked. It’s not just about following steps; it’s about understanding the logic behind them. So, take a moment, jot down a few multiples of 6767, and get familiar with it. This preparation will save you time and prevent silly errors later on. Remember, a solid setup makes the rest of the journey much smoother. We are aiming for accuracy and understanding, not just speed. This foundational step ensures we're on the right track from the get-go.

Step 2: The First Digit of the Quotient

We start from the leftmost digit of the dividend. Can 6767 go into 88? Nope, 88 is way too small. So, we look at the first two digits of the dividend: 8282. Now, the question is, how many times does 6767 go into 8282? Think about it: 67×1=6767 \times 1 = 67. 67×2=13467 \times 2 = 134. Clearly, 6767 only goes into 8282 one time. So, we write 11 above the 22 in the dividend (since we used the first two digits, 8282, to figure this out). This 11 is the first digit of our quotient.

      1_____
67 | 825470

Next, we multiply the digit we just placed in the quotient (11) by the divisor (6767). So, 1×67=671 \times 67 = 67. We write this 6767 underneath the 8282 in the dividend.

      1_____
67 | 825470
     67

Finally, we subtract 6767 from 8282. 8267=1582 - 67 = 15. Write the result, 1515, underneath the line.

      1_____
67 | 825470
     -67
      ---
       15

This process – divide, multiply, subtract – is the core loop of long division. You're essentially figuring out how many groups of the divisor fit into a portion of the dividend, finding out how much is left over, and then bringing down the next digit to repeat the process. It's like peeling an onion, layer by layer. Each step refines our approximation until we get to the final answer. The remainder 1515 tells us that 6767 went into 8282 once, with 1515 left over. We haven't even touched the 55, 44, 77, or 00 yet! This first step is crucial for setting the stage for the rest of the division. Mastering this initial 'divide, multiply, subtract' cycle is key to unlocking the entire problem. Keep it up, you're doing great!

Step 3: Bringing Down the Next Digit

Now that we have our remainder, 1515, we need to bring down the next digit from the dividend. The next digit after 22 is 55. So, we bring the 55 down and place it next to the 1515, forming the new number 155155.

      1_____
67 | 825470
     -67
      ---
       155 

This new number, 155155, becomes the focus for our next round of division. The question now is: how many times does 6767 go into 155155? Let's think about our multiples of 6767 again. We know 67×1=6767 \times 1 = 67 and 67×2=13467 \times 2 = 134. If we try 67×367 \times 3, that would be 134+67=201134 + 67 = 201, which is too big. So, 6767 goes into 155155 exactly two times. We write this 22 in the quotient, directly above the 55 we just brought down.

      12____
67 | 825470
     -67
      ---
       155 

Just like before, the next step is to multiply the new quotient digit (22) by the divisor (6767). 2×67=1342 \times 67 = 134. We write this 134134 underneath the 155155.

      12____
67 | 825470
     -67
      ---
       155 
      134

And then, we subtract: 155134=21155 - 134 = 21. Write this remainder, 2121, below the line.

      12____
67 | 825470
     -67
      ---
       155 
      -134
       ---
        21

See the pattern, guys? Bring down, divide, multiply, subtract. It's a continuous cycle! We've now dealt with the 88, 22, and 55. We have a remainder of 2121, and we still have the 44, 77, and 00 waiting in the wings. Each step gets us closer to the final answer, and the remainders are just temporary placeholders until we bring down the next digit. This iterative process is what makes long division so powerful. It breaks a large, seemingly impossible problem into a series of smaller, manageable steps. Keep focusing on that 'bring down, divide, multiply, subtract' rhythm, and you'll be acing this in no time. We're making great progress here!

Step 4: Continuing the Process

We've got a remainder of 2121 after dealing with 155155. What's the next step? You guessed it – bring down the next digit! Our next digit is 44. So, we bring the 44 down next to the 2121, forming the new number 214214.

      12____
67 | 825470
     -67
      ---
       155 
      -134
       ---
        214

Now, we ask: how many times does 6767 go into 214214? This one might require a bit more estimation. We know 67×2=13467 \times 2 = 134. Let's try 67×367 \times 3. 67×3=(60×3)+(7×3)=180+21=20167 \times 3 = (60 \times 3) + (7 \times 3) = 180 + 21 = 201. What about 67×467 \times 4? That would be 201+67=268201 + 67 = 268, which is too big. So, 6767 goes into 214214 exactly three times. We write this 33 in the quotient, above the 44.

      123___
67 | 825470
     -67
      ---
       155 
      -134
       ---
        214

Time to multiply: 3×67=2013 \times 67 = 201. Write 201201 under 214214.

      123___
67 | 825470
     -67
      ---
       155 
      -134
       ---
        214
        201

And subtract: 214201=13214 - 201 = 13. Write the remainder 1313 below.

      123___
67 | 825470
     -67
      ---
       155 
      -134
       ---
        214
       -201
        ---
         13

We're still going strong! We've used the 8,2,5,8, 2, 5, and 44. We have a remainder of 1313, and still have the 77 and 00 to go. It's a marathon, not a sprint, guys, and each step is bringing us closer to that final answer. The key is to stay organized and follow the 'bring down, divide, multiply, subtract' mantra. Don't get discouraged by the multiple steps; each one is just building on the last. You're doing an awesome job breaking down this complex problem into manageable chunks!

Step 5: The Final Digits

We have our remainder 1313, and the next digit to bring down is 77. So, we form the new number 137137.

      123___
67 | 825470
     -67
      ---
       155 
      -134
       ---
        214
       -201
        ---
         137

How many times does 6767 go into 137137? We already know 67×1=6767 \times 1 = 67 and 67×2=13467 \times 2 = 134. 67×3=20167 \times 3 = 201, which is too big. So, 6767 goes into 137137 exactly two times. Write 22 in the quotient above the 77.

      1232_
67 | 825470
     -67
      ---
       155 
      -134
       ---
        214
       -201
        ---
         137

Multiply: 2×67=1342 \times 67 = 134. Write 134134 under 137137.

      1232_
67 | 825470
     -67
      ---
       155 
      -134
       ---
        214
       -201
        ---
         137
         134

Subtract: 137134=3137 - 134 = 3. Write the remainder 33 below.

      1232_
67 | 825470
     -67
      ---
       155 
      -134
       ---
        214
       -201
        ---
         137
        -134
         ---
           3

We're in the home stretch! We've used the 8,2,5,4,8, 2, 5, 4, and 77. We have a remainder of 33, and only one digit left: 00. Bring down the 00 next to the 33 to make 3030.

      1232_
67 | 825470
     -67
      ---
       155 
      -134
       ---
        214
       -201
        ---
         137
        -134
         ---
           30

Now, the final question: how many times does 6767 go into 3030? Since 3030 is smaller than 6767, 6767 goes into 3030 zero times. Write 00 in the quotient above the 00.

      12320
67 | 825470
     -67
      ---
       155 
      -134
       ---
        214
       -201
        ---
         137
        -134
         ---
           30

Multiply: 0×67=00 \times 67 = 0. Write 00 under 3030.

      12320
67 | 825470
     -67
      ---
       155 
      -134
       ---
        214
       -201
        ---
         137
        -134
         ---
           30
           0

Subtract: 300=3030 - 0 = 30. Write the remainder 3030 below.

      12320
67 | 825470
     -67
      ---
       155 
      -134
       ---
        214
       -201
        ---
         137
        -134
         ---
           30
          -0
          --
           30

We've used all the digits of the dividend! Since 3030 is smaller than 6767, we can't divide further. This 3030 is our final remainder.

Step 6: The Answer

So, after all that hard work, we've arrived at our answer! The quotient is 12,32012,320 and the remainder is 3030. We can write this as:

825,470÷67=12,320 R 30825,470 \div 67 = 12,320 \text{ R } 30

To check our work, we can use the formula: Dividend = (Divisor × Quotient) + Remainder. Let's plug in our numbers:

(67×12,320)+30(67 \times 12,320) + 30

First, 67×12,320=825,44067 \times 12,320 = 825,440.

Then, 825,440+30=825,470825,440 + 30 = 825,470.

And voilà! It matches our original dividend. This verification step is super important, guys. It confirms that our long division was accurate and that we haven't made any calculation errors along the way. It's like double-checking your work before submitting an important assignment. This process of breaking down large numbers into smaller, manageable steps is the essence of long division. Remember the cycle: Divide, Multiply, Subtract, Bring Down. Practice makes perfect, so don't hesitate to try more problems. You've got this!