Simplify Algebraic Expression: Fractions

by Andrew McMorgan 41 views

Hey guys, today we're diving into the awesome world of simplifying algebraic expressions, specifically tackling a fraction that looks a little intimidating at first glance. You know the drill – those complex fractions with variables can sometimes make your head spin, but trust me, with a few key steps, we can break it down into something super manageable. Our mission, should we choose to accept it, is to simplify this beast:

1+xy1βˆ’x2y2=\frac{1+\frac{x}{y}}{1-\frac{x^2}{y^2}}=

We've also got some options to choose from: A. yyβˆ’x\frac{y}{y-x} B. yβˆ’xy\frac{y-x}{y} C. βˆ’yx\frac{-y}{x}

Let's get this party started and figure out which one is the correct answer. This kind of problem is super common in algebra, and mastering it will give you a serious leg up in your math journey. So, grab your favorite drink, get comfortable, and let's break down this fraction step by step. We'll be looking at common denominators, factoring, and cancelling out terms – all the good stuff that makes algebra cool.

Understanding Complex Fractions

Alright, let's talk about complex fractions. What makes a fraction complex? It's basically a fraction where the numerator, the denominator, or both contain fractions themselves. Our expression, 1+xy1βˆ’x2y2\frac{1+\frac{x}{y}}{1-\frac{x^2}{y^2}}, is a perfect example of a complex fraction because both the numerator (1+xy1+\frac{x}{y}) and the denominator (1βˆ’x2y21-\frac{x^2}{y^2}) have fractional parts. When you see a complex fraction, your main goal is to simplify it into a simple fraction – one with just a single number or expression on top and a single number or expression on the bottom. This usually involves finding common denominators for the parts of the numerator and denominator, and then multiplying by the reciprocal of the denominator. It sounds a bit like a recipe, right? Don't worry, we'll walk through it, and you'll see that it's not as scary as it looks. The strategy is always to simplify the numerator and the denominator separately first, and then combine them. This makes the whole process much cleaner and less prone to errors. Think of it like untangling a knot – you take it one step at a time, and before you know it, it's all sorted out. So, when you encounter these, just take a deep breath, identify the numerator and denominator, and get ready to simplify those parts. It's a fundamental skill in algebra that opens doors to solving more advanced problems and understanding more complex mathematical concepts. Keep this strategy in mind, and you'll be a complex fraction wizard in no time!

Step-by-Step Simplification

Let's get down to business and simplify our expression, 1+xy1βˆ’x2y2\frac{1+\frac{x}{y}}{1-\frac{x^2}{y^2}}. Our first move is to simplify the numerator and the denominator independently.

Simplifying the Numerator:

The numerator is 1+xy1+\frac{x}{y}. To combine these, we need a common denominator, which is clearly yy. So, we rewrite 11 as yy\frac{y}{y}.

1+xy=yy+xy=y+xy1 + \frac{x}{y} = \frac{y}{y} + \frac{x}{y} = \frac{y+x}{y}

Simplifying the Denominator:

The denominator is 1βˆ’x2y21-\frac{x^2}{y^2}. Again, we need a common denominator, which is y2y^2. We rewrite 11 as y2y2\frac{y^2}{y^2}.

1βˆ’x2y2=y2y2βˆ’x2y2=y2βˆ’x2y21 - \frac{x^2}{y^2} = \frac{y^2}{y^2} - \frac{x^2}{y^2} = \frac{y^2-x^2}{y^2}

Now, let's put these simplified parts back into our original complex fraction:

y+xyy2βˆ’x2y2\frac{\frac{y+x}{y}}{\frac{y^2-x^2}{y^2}}

This looks much better, right? We've turned a complex fraction into a fraction divided by another fraction. The next step in dealing with a fraction divided by a fraction is to multiply the numerator by the reciprocal of the denominator.

So, we flip the bottom fraction and multiply:

(y+xy)Γ—(y2y2βˆ’x2)(\frac{y+x}{y}) \times (\frac{y^2}{y^2-x^2})

Now we multiply the numerators together and the denominators together:

(y+x)y2y(y2βˆ’x2) \frac{(y+x)y^2}{y(y^2-x^2)}

Before we go further, we should look for opportunities to cancel out common factors. This is where the magic happens, and we get closer to our final simplified answer. Let's examine the terms. We have (y+x)(y+x) in the numerator and (y2βˆ’x2)(y^2-x^2) in the denominator. Remember that y2βˆ’x2y^2-x^2 is a difference of squares, which can be factored as (yβˆ’x)(y+x)(y-x)(y+x). This is a crucial step!

So, we can rewrite the denominator as y(yβˆ’x)(y+x)y(y-x)(y+x).

Our expression now looks like this:

(y+x)y2y(yβˆ’x)(y+x) \frac{(y+x)y^2}{y(y-x)(y+x)}

Do you see the common factors? We have (y+x)(y+x) in both the numerator and the denominator. We can cancel these out! We also have y2y^2 in the numerator and yy in the denominator. We can cancel out one factor of yy from both.

(y+x)y2y(yβˆ’x)(y+x)=yyβˆ’x \frac{\cancel{(y+x)}y^{\cancel{2}}}{ \cancel{y} (y-x) \cancel{(y+x)}} = \frac{y}{y-x}

And there you have it! We've simplified the complex fraction into a simple one. It took a few steps – finding common denominators, rewriting, and factoring – but by breaking it down, we got to the answer.

Identifying the Correct Option

So, after all that hard work, we arrived at the simplified expression yyβˆ’x\frac{y}{y-x}. Now, let's compare this to the options provided:

A. yyβˆ’x\frac{y}{y-x} B. yβˆ’xy\frac{y-x}{y} C. βˆ’yx\frac{-y}{x}

Our result, yyβˆ’x\frac{y}{y-x}, exactly matches Option A. This means that Option A is the correct answer to our problem. It’s always super satisfying when your calculated answer lines up perfectly with one of the choices, right? It validates all the steps you took and confirms your understanding. Remember, the key to these kinds of problems is patience and a systematic approach. Don't rush, double-check your algebra, and always look for opportunities to factor and cancel. This particular problem tested our ability to handle complex fractions, find common denominators, and factor a difference of squares, which are all fundamental skills in algebra. Practicing these types of problems regularly will build your confidence and speed. So next time you see a complex fraction, you'll know exactly how to tackle it! Keep up the great work, guys!

Conclusion

We've successfully navigated the choppy waters of a complex algebraic fraction! By systematically simplifying the numerator and denominator, finding common denominators, and then cleverly factoring and canceling terms, we were able to reduce the expression 1+xy1βˆ’x2y2\frac{1+\frac{x}{y}}{1-\frac{x^2}{y^2}} down to its simplest form, which is yyβˆ’x\frac{y}{y-x}. This matches option A, proving that with a solid understanding of algebraic manipulation, even the most tangled expressions can be unraveled. Remember the power of finding common denominators and the elegance of factoring, especially the difference of squares, a2βˆ’b2=(aβˆ’b)(a+b)a^2 - b^2 = (a-b)(a+b). These tools are your best friends when simplifying fractions. Keep practicing these skills, and you'll find yourself breezing through algebraic simplification problems. Math is all about building blocks, and mastering complex fractions is a significant step. Keep those brains buzzing, and we'll tackle more exciting math challenges soon! Stay curious, stay mathematical!