Simplify The Expression $\frac{2}{3}(4-12w)$

by Andrew McMorgan 45 views

Hey math lovers! Today, we're diving into a cool algebraic expression that's super common in your math classes: 23(4βˆ’12w)\frac{2}{3}(4-12w). You might see this in problems involving equations, functions, or even geometric shapes. Our goal here is to simplify it, which basically means making it shorter and easier to work with without changing its value. Think of it like tidying up your room – you're making it neater and more manageable. Simplifying expressions is a fundamental skill, and mastering it will make tackling more complex math problems a breeze. So, grab your calculators, sharpen your pencils, and let's break down this expression step-by-step.

Understanding the Basics of Simplification

Before we jump into our specific expression, let's quickly recap what simplification means in algebra, guys. Simplifying an expression usually involves two main operations: the distributive property and combining like terms. The distributive property is like a rule that says when you have a number or a fraction outside parentheses, you multiply it by each term inside the parentheses. For example, in a(b+c)a(b+c), you do aΓ—ba \times b and aΓ—ca \times c to get ab+acab + ac. It's super handy for removing parentheses. Then, combining like terms means adding or subtracting terms that have the same variable raised to the same power. For instance, in 3x+5xβˆ’23x + 5x - 2, the 3x3x and 5x5x are like terms because they both have an xx. You can combine them to get 8x8x, making the expression 8xβˆ’28x - 2. If you had terms like 2y2y and 77, they aren't like terms, so you can't combine them. Our expression, 23(4βˆ’12w)\frac{2}{3}(4-12w), involves both of these concepts. We'll start by distributing the fraction 23\frac{2}{3} to both the 4 and the βˆ’12w-12w inside the parentheses. This will help us get rid of the parentheses and prepare the expression for any further simplification if needed. Remember, the key is to perform operations accurately and systematically. Don't be afraid to write down each step clearly; it's the best way to avoid silly mistakes and build confidence in your algebraic skills. We're going to break down 23(4βˆ’12w)\frac{2}{3}(4-12w) in a way that’s easy to follow, so even if fractions and variables make you a bit nervous, you’ll be able to nail this.

Step-by-Step Simplification of 23(4βˆ’12w)\frac{2}{3}(4-12w)

Alright, let's get down to business with 23(4βˆ’12w)\frac{2}{3}(4-12w). The first thing we need to do is apply the distributive property. This means we're going to multiply the 23\frac{2}{3} by each term inside the parentheses: the 4 and the βˆ’12w-12w. So, the first multiplication is 23Γ—4\frac{2}{3} \times 4, and the second multiplication is 23Γ—(βˆ’12w)\frac{2}{3} \times (-12w).

Let's tackle the first part: 23Γ—4\frac{2}{3} \times 4. To multiply a fraction by a whole number, you can think of the whole number as a fraction with a denominator of 1. So, it becomes 23Γ—41\frac{2}{3} \times \frac{4}{1}. When you multiply fractions, you multiply the numerators together and the denominators together. This gives us 2Γ—43Γ—1\frac{2 \times 4}{3 \times 1}, which equals 83\frac{8}{3}. So, the first term after distribution is 83\frac{8}{3}.

Now, let's move on to the second part: 23Γ—(βˆ’12w)\frac{2}{3} \times (-12w). This is similar, but we have a variable involved. First, let's handle the numbers: 23Γ—(βˆ’12)\frac{2}{3} \times (-12). Again, we can write -12 as βˆ’121\frac{-12}{1}. So we have 23Γ—βˆ’121\frac{2}{3} \times \frac{-12}{1}. Multiplying the numerators gives us 2Γ—(βˆ’12)=βˆ’242 \times (-12) = -24. Multiplying the denominators gives us 3Γ—1=33 \times 1 = 3. This results in βˆ’243\frac{-24}{3}.

Now, we need to simplify this fraction, βˆ’243\frac{-24}{3}. We can divide -24 by 3. How many times does 3 go into 24? It's 8 times. Since we have a negative number, the result is -8. So, βˆ’243\frac{-24}{3} simplifies to -8. Since we were multiplying by βˆ’12w-12w, the result of 23Γ—(βˆ’12w)\frac{2}{3} \times (-12w) is βˆ’8w-8w.

Putting it all together, after distributing 23\frac{2}{3} to both terms inside the parentheses, our expression becomes 83+(βˆ’8w)\frac{8}{3} + (-8w). A plus a negative is just a minus, so this simplifies to 83βˆ’8w\frac{8}{3} - 8w. This is our simplified expression! We've successfully removed the parentheses and made the expression more concise.

Final Simplified Form and Why It Matters

So, after all that hard work, the simplified form of 23(4βˆ’12w)\frac{2}{3}(4-12w) is 83βˆ’8w\frac{8}{3} - 8w. You'll notice that we can't simplify this any further because 83\frac{8}{3} is a constant term (a number without any variables) and βˆ’8w-8w is a variable term (it has the variable ww). These are not like terms, so we can't combine them. This final form is much cleaner and easier to use in subsequent calculations. For instance, if you were asked to solve an equation like 23(4βˆ’12w)=5\frac{2}{3}(4-12w) = 5, you would first simplify the left side to get 83βˆ’8w=5\frac{8}{3} - 8w = 5. This makes solving for ww much more straightforward. You could then subtract 83\frac{8}{3} from both sides and then divide by -8.

Understanding how to simplify expressions like this is a cornerstone of algebra, guys. It's not just about getting the right answer on a test; it's about developing logical thinking and problem-solving skills that are applicable to countless areas, both in math and in life. When you can simplify a complex expression, you gain a clearer understanding of the underlying relationships and can manipulate mathematical statements more effectively. Think of it like learning a new language – the more vocabulary and grammar you master (like the distributive property and combining like terms), the more fluently you can express yourself and understand complex ideas. So, the next time you see an expression like 23(4βˆ’12w)\frac{2}{3}(4-12w), don't shy away from it. Break it down, apply the rules you've learned, and remember that every step you take is building your mathematical muscle. Keep practicing, and you'll be simplifying like a pro in no time! You've got this!