Solve & Graph Inequalities: A Step-by-Step Guide

by Andrew McMorgan 49 views

Hey guys! Ever get stuck staring at an inequality, wondering how on earth you're supposed to find the answer and then actually show it on a graph? Well, you've come to the right place! Today, we're diving deep into the world of solving and graphing inequalities, using the example 4(āˆ’2n2+2.5)āˆ’8≤504\left(-2 n^2+2.5\right)-8 \leq 50 to guide us. This isn't just about crunching numbers; it's about understanding what these symbols mean and how to visually represent them. We'll break down every single step, from simplifying the inequality to plotting the final solution on a number line. So grab your notebooks, maybe a snack, and let's get this mathematical party started!

Understanding the Inequality: What's the Big Deal?

First off, let's chat about what an inequality is. Unlike an equation, which states that two things are equal (think x=5x=5), an inequality says that two things are not equal in a specific way. We've got our trusty symbols: '<' (less than), '>' (greater than), 'leq\\leq' (less than or equal to), and '′\\'=' (greater than or equal to). These little symbols are super important because they tell us a whole range of possible answers, not just a single one. In our case, 4(āˆ’2n2+2.5)āˆ’8≤504\left(-2 n^2+2.5\right)-8 \leq 50 means we're looking for all the values of 'n' that make the left side of the expression less than or equal to 50. This concept of a range is what makes graphing inequalities so crucial – it's the best way to visualize all those possible solutions. We'll be simplifying this beast step-by-step, making sure we don't miss any details. Remember, solving inequalities often involves similar steps to solving equations, but you have to be extra careful when multiplying or dividing by a negative number, as that flips the inequality sign. But don't worry, we'll cover all that jazz!

Step 1: Simplify and Isolate the Variable Term

Alright, team, let's get our hands dirty with the actual solving part. Our inequality is 4(āˆ’2n2+2.5)āˆ’8≤504\left(-2 n^2+2.5\right)-8 \leq 50. The first thing we wanna do is simplify the left side of the inequality. We've got parentheses, so let's distribute that 4: 4Ć—āˆ’2n24 \times -2n^2 is āˆ’8n2-8n^2, and 4Ɨ2.54 \times 2.5 is 10. So now our inequality looks like this: āˆ’8n2+10āˆ’8≤50-8n^2 + 10 - 8 \leq 50. See? Already looking a bit tidier! Next, let's combine those constant terms on the left side: 10āˆ’810 - 8 is just 2. So, we're left with āˆ’8n2+2≤50-8n^2 + 2 \leq 50. Our goal now is to isolate the n2n^2 term. To do that, we'll subtract 2 from both sides of the inequality: āˆ’8n2+2āˆ’2≤50āˆ’2-8n^2 + 2 - 2 \leq 50 - 2. This simplifies to āˆ’8n2≤48-8n^2 \leq 48. We're getting closer, guys! The variable term, āˆ’8n2-8n^2, is now isolated. This is a big win! Keep your eyes peeled for the next steps, as we'll be dealing with that pesky coefficient in front of n2n^2. Remember, the key is to perform operations on both sides to maintain the balance of the inequality.

Step 2: Isolate the Variable (n²)

Okay, we're at the stage where we have āˆ’8n2≤48-8n^2 \leq 48. Now, we need to get n2n^2 all by its lonesome. To do this, we need to divide both sides by -8. And here's where we gotta pay super close attention, folks! When you divide or multiply both sides of an inequality by a negative number, you must flip the direction of the inequality sign. This is super important and a common place to trip up. So, dividing both sides by -8, and flipping the sign, we get: fracāˆ’8n2āˆ’8geqfrac48āˆ’8\\frac{-8n^2}{-8} \\geq \\frac{48}{-8}. This simplifies beautifully to n2geqāˆ’6n^2 \\geq -6. Woah, check it out! We've managed to isolate n2n^2. This step is critical because it sets us up for finding the actual values of 'n'. Remember that rule about flipping the sign – it's a lifesaver! Keep this in mind as we move forward; understanding these nuances is what separates a good grasp of inequalities from a great one.

Step 3: Solving for 'n' and Considering the Nature of Square Roots

We've arrived at n2geqāˆ’6n^2 \\geq -6. Now, we need to solve for 'n'. To get 'n' by itself, we'd normally take the square root of both sides. So, we'd have ngeqsqrtāˆ’6n \\geq \\sqrt{-6} and nleqāˆ’sqrtāˆ’6n \\leq -\\sqrt{-6}. However, there's a little snag here, guys. The square root of a negative number isn't a real number! We're dealing with real number solutions here. So, what does n2geqāˆ’6n^2 \\geq -6 actually mean in the realm of real numbers? Well, any real number, when squared (multiplied by itself), will always result in a non-negative number (zero or positive). For example, 32=93^2 = 9, (āˆ’3)2=9(-3)^2 = 9, and 02=00^2 = 0. Since n2n^2 will always be greater than or equal to 0 for any real number 'n', and 0 is definitely greater than -6, the inequality n2geqāˆ’6n^2 \\geq -6 is always true for all real numbers 'n'. That means our solution set is all real numbers! This is a really cool outcome and shows how important it is to think about the properties of the numbers we're working with. It's not always about simple algebraic manipulation; sometimes it's about understanding the fundamental nature of numbers themselves.

Step 4: Graphing the Solution Set

So, we've figured out that our inequality 4(āˆ’2n2+2.5)āˆ’8≤504\left(-2 n^2+2.5\right)-8 \leq 50 is true for all real numbers. Now comes the fun part: graphing this solution. When we graph inequalities, we use a number line. For our case, since every single real number is a solution, we need a way to show this on the number line. We'll draw a standard number line with some key points marked, like -2, -1, 0, 1, 2, etc. Because our solution includes all real numbers, we'll use a special notation. We don't use an open or closed circle at a specific point because there isn't one! Instead, we shade the entire number line. This shading indicates that every single point on that line represents a valid solution to our original inequality. It's like saying,