Solve Y=3x-1 For X=-1

by Andrew McMorgan 22 views

Solving for the Value of a Function

Hey guys! Ever found yourself staring at a math problem and thinking, "What on earth is this asking?" Well, you're in the right place. Today, we're diving deep into a super common type of question in mathematics: evaluating a function. Specifically, we're going to crack the code on how to find the value of the function y=3xβˆ’1y=3x-1 when xx is given as βˆ’1-1. This skill is fundamental, like learning your ABCs for reading, and it pops up everywhere, from your algebra class to more complex calculus problems.

Let's break down what a function actually is, for all you math newbies out there. Think of a function as a machine. You put something in (that's your input, usually represented by 'x'), and the machine does something to it according to a specific rule. What comes out is your output (usually represented by 'y' or f(x)f(x)). In our case, the function is y=3xβˆ’1y=3x-1. This means our 'machine' takes an input 'x', multiplies it by 3, and then subtracts 1. Pretty straightforward, right?

The problem asks us to find the value of this function when x=βˆ’1x=-1. This is like being told, "Okay, the input for our machine is -1. What's the output going to be?" Our mission, should we choose to accept it, is to substitute that given value of xx into the function's equation and calculate the result. It's all about substitution and then following the order of operations. We're not just randomly plugging numbers in; we're strategically replacing the variable 'x' with the specific value βˆ’1-1. This process is crucial for understanding how functions behave and how their outputs change based on different inputs. So, get ready to roll up your sleeves and do some calculation, because we're about to find out exactly what yy equals when xx decides to be βˆ’1-1.

The Core Concept: Substitution in Functions

Alright, let's get down to the nitty-gritty of function evaluation. When we talk about a function like y=3xβˆ’1y=3x-1, the 'yy' is essentially a placeholder for the output, and 'xx' is the placeholder for the input. The equation y=3xβˆ’1y=3x-1 tells us the rule the function follows: take the input 'xx', multiply it by 3, and then subtract 1 from the result to get the output 'yy'. Now, the question pins down a specific input: 'x=βˆ’1x=-1'. What we need to do is substitute this value of βˆ’1-1 for every instance of 'xx' in the equation. It's like saying, "Okay, for this specific moment, xx isn't just any number; it's exactly βˆ’1-1. Let's see what happens."

So, we take our equation: y=3xβˆ’1y = 3x - 1. And we replace 'xx' with 'βˆ’1-1'. This gives us: y=3(βˆ’1)βˆ’1y = 3(-1) - 1. Notice how we put the βˆ’1-1 in parentheses. This is a good habit, especially when dealing with negative numbers, to avoid any confusion with multiplication signs or subtraction. It clearly shows that the entire value of βˆ’1-1 is being multiplied by 3.

Once the substitution is done, the next step is pure arithmetic, focusing on the order of operations (often remembered by the acronym PEMDAS/BODMAS: Parentheses/Brackets, Exponents/Orders, Multiplication and Division from left to right, Addition and Subtraction from left to right). In our equation, y=3(βˆ’1)βˆ’1y = 3(-1) - 1, we first perform the multiplication: 3imesβˆ’13 imes -1. Multiplying a positive number by a negative number always results in a negative number. So, 3imesβˆ’1=βˆ’33 imes -1 = -3. Our equation now simplifies to: y=βˆ’3βˆ’1y = -3 - 1.

Finally, we perform the subtraction: βˆ’3βˆ’1-3 - 1. When you subtract 1 from βˆ’3-3, you are moving further down the number line into more negative territory. Think of it as owing someone $3 and then having to pay back another $1; you now owe a total of $4. Therefore, βˆ’3βˆ’1=βˆ’4-3 - 1 = -4. And there you have it! The value of the function y=3xβˆ’1y=3x-1 when x=βˆ’1x=-1 is βˆ’4-4. This process of substitution and calculation is the heart of understanding how functions work and predicting their outcomes for various inputs. It’s a fundamental building block in mathematics, and mastering it opens doors to tackling more complex problems with confidence. Keep practicing this, guys, and you'll be a function-evaluating pro in no time!

Step-by-Step Calculation Breakdown

Let's really break down the calculation step-by-step, so nobody gets left behind, especially if you're just starting out with these kinds of problems. Our goal is to find the value of yy in the equation y=3xβˆ’1y = 3x - 1 when we are given that x=βˆ’1x = -1. This is a classic function evaluation scenario. The function is our rule, and x=βˆ’1x=-1 is the specific input we're interested in.

Step 1: Identify the Function and the Input Value.

First off, we clearly state what we have. The function is y=3xβˆ’1y = 3x - 1. The given input value for xx is βˆ’1-1. It’s super important to correctly identify these two pieces of information. Sometimes the input might be given in a slightly different format, like f(βˆ’1)f(-1), which means the same thing: find the output of function ff when the input is βˆ’1-1. In our case, yy is the output, and xx is the input. We are told xx is βˆ’1-1.

Step 2: Substitute the Input Value into the Function.

This is where the magic happens! We take the variable 'xx' in our equation y=3xβˆ’1y = 3x - 1 and replace it with the specific value we were given, which is βˆ’1-1. It’s crucial to use parentheses around the substituted value, especially if it's negative or if there are multiple terms involved in the function. This helps maintain clarity and avoid errors. So, the equation becomes: y=3(βˆ’1)βˆ’1y = 3(-1) - 1. The parentheses around βˆ’1-1 signify that the entire number βˆ’1-1 is being multiplied by 3.

Step 3: Perform the Multiplication.

Following the order of operations (PEMDAS/BODMAS), multiplication comes before subtraction. We need to calculate 3imes(βˆ’1)3 imes (-1). Remember the rules for multiplying integers: a positive number multiplied by a negative number gives a negative result. So, 3imes(βˆ’1)=βˆ’33 imes (-1) = -3. Our equation now looks like this: y=βˆ’3βˆ’1y = -3 - 1.

Step 4: Perform the Subtraction.

The final step is to perform the remaining operation, which is subtraction. We have y=βˆ’3βˆ’1y = -3 - 1. Subtracting 1 from βˆ’3-3 means we are moving 1 unit further to the left on the number line. Starting at βˆ’3-3 and moving left by 1 unit brings us to βˆ’4-4. So, βˆ’3βˆ’1=βˆ’4-3 - 1 = -4. Alternatively, you can think of this as adding two negative numbers: βˆ’3+(βˆ’1)=βˆ’4-3 + (-1) = -4. Both interpretations lead to the same correct answer.

Step 5: State the Final Answer.

We have successfully completed the evaluation. The value of the function y=3xβˆ’1y = 3x - 1 when x=βˆ’1x = -1 is βˆ’4-4. So, we can write our final answer as y=βˆ’4y = -4. You did it, guys! This systematic approachβ€”identify, substitute, calculate (multiplication first, then subtraction)β€”ensures accuracy every time. Keep practicing these steps, and soon you'll be able to do them mentally!

Practical Applications and Why This Matters

Okay, so we've crunched the numbers and found that when xx is βˆ’1-1, the function y=3xβˆ’1y=3x-1 gives us y=βˆ’4y=-4. That's great for this specific problem, but you might be wondering, "Why should I care? Does this math stuff actually matter in the real world?" The answer is a resounding YES! Understanding how to evaluate functions is a foundational skill that has tons of practical applications, even if you don't realize it.

Think about modeling real-world situations. Many phenomena in science, economics, engineering, and even everyday life can be described using mathematical functions. For example, let's say you're tracking the growth of a plant. You might have a function that estimates the plant's height (yy) based on the number of days since it was planted (xx). If your function is something like y=0.5x+2y = 0.5x + 2 (meaning it starts at 2 cm and grows 0.5 cm per day), evaluating it for a specific number of days, say x=10x=10, tells you the estimated height after 10 days. Plugging in x=10x=10 gives y=0.5(10)+2=5+2=7y = 0.5(10) + 2 = 5 + 2 = 7 cm. This kind of prediction is vital for planning and understanding trends.

In computer programming, functions are everywhere! When you write a piece of code that performs a specific task, it's often encapsulated in a function. You pass values (inputs) into the function, and it returns a result (output). Understanding function evaluation helps programmers predict how their code will behave with different inputs, which is crucial for debugging and creating efficient programs. Our simple y=3xβˆ’1y=3x-1 function could represent a basic calculation within a larger software.

Consider financial scenarios. If you have a function describing your monthly expenses based on the number of hours you work, evaluating it for different work hours helps you budget. Maybe y=10x+500y = 10x + 500, where yy is total monthly expenses and xx is hours worked overtime (with a fixed cost of 500).Ifyouwork20hoursofovertime(500). If you work 20 hours of overtime (x=20$), your expenses would be y=10(20)+500=200+500=700y = 10(20) + 500 = 200 + 500 = 700. This helps you make informed financial decisions.

Even simple things like calculating the cost of items can involve functions. If a store sells T-shirts for 15each,thetotalcost(15 each, the total cost (y$) for buying xx T-shirts can be represented by the function y=15xy = 15x. If you want to know the cost of 3 T-shirts, you evaluate the function at x=3x=3: y=15(3)=45y = 15(3) = 45. So, it costs $45 for 3 T-shirts.

Essentially, function evaluation is the process of asking "what happens if?" in a structured, mathematical way. It allows us to test hypotheses, make predictions, and understand relationships between different quantities. The ability to substitute a value for a variable and compute the result is the bedrock upon which much of advanced mathematics and its applications are built. So, the next time you're solving a function evaluation problem, remember that you're practicing a skill that's incredibly powerful and relevant, guys. It's not just abstract math; it's a tool for understanding and shaping the world around us. Keep practicing, and you'll see just how far this skill can take you!